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.6x^2-x-8=0
We add all the numbers together, and all the variables
.6x^2-1x-8=0
a = .6; b = -1; c = -8;
Δ = b2-4ac
Δ = -12-4·.6·(-8)
Δ = 20.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{20.2}}{2*.6}=\frac{1-\sqrt{20.2}}{1.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{20.2}}{2*.6}=\frac{1+\sqrt{20.2}}{1.2} $
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